To find equation solutions, solve x=0 and x2=0 x^ {2}2x=0 All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions, one when ±
Y=x^2-6x+8 range-2xy=8 2 x y = 8 Subtract y from both sides Subtract y from both sides 2x=8y 2 x = 8 − y Divide both sides by 2 Divide both sides by 2 \frac {2x} {2}=\frac {8y} {2}Math Input Use Math Input Mode to directly enter textbook math notation Try it
Y=x^2-6x+8 rangeのギャラリー
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